Ten slips of paper labeled from 1 to 10 are placed in a hat. The first slip of paper is not replaced before selecting the second slip of paper. What is the probability of selecting a number less than 2 then a number greater than 7
Accepted Solution
A:
You will multiply the number if favorable outcomes over the number of total outcomes [tex] \frac{1}{10} \times \frac{3}{9} = \frac{3}{90} = \frac{1}{30} [/tex]